mirror of
https://github.com/git/git.git
synced 2024-11-05 16:52:59 +01:00
382 lines
11 KiB
C
382 lines
11 KiB
C
|
/*
|
||
|
* LibXDiff by Davide Libenzi ( File Differential Library )
|
||
|
* Copyright (C) 2003-2009 Davide Libenzi, Johannes E. Schindelin
|
||
|
*
|
||
|
* This library is free software; you can redistribute it and/or
|
||
|
* modify it under the terms of the GNU Lesser General Public
|
||
|
* License as published by the Free Software Foundation; either
|
||
|
* version 2.1 of the License, or (at your option) any later version.
|
||
|
*
|
||
|
* This library is distributed in the hope that it will be useful,
|
||
|
* but WITHOUT ANY WARRANTY; without even the implied warranty of
|
||
|
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
|
||
|
* Lesser General Public License for more details.
|
||
|
*
|
||
|
* You should have received a copy of the GNU Lesser General Public
|
||
|
* License along with this library; if not, write to the Free Software
|
||
|
* Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
|
||
|
*
|
||
|
* Davide Libenzi <davidel@xmailserver.org>
|
||
|
*
|
||
|
*/
|
||
|
#include "xinclude.h"
|
||
|
#include "xtypes.h"
|
||
|
#include "xdiff.h"
|
||
|
|
||
|
/*
|
||
|
* The basic idea of patience diff is to find lines that are unique in
|
||
|
* both files. These are intuitively the ones that we want to see as
|
||
|
* common lines.
|
||
|
*
|
||
|
* The maximal ordered sequence of such line pairs (where ordered means
|
||
|
* that the order in the sequence agrees with the order of the lines in
|
||
|
* both files) naturally defines an initial set of common lines.
|
||
|
*
|
||
|
* Now, the algorithm tries to extend the set of common lines by growing
|
||
|
* the line ranges where the files have identical lines.
|
||
|
*
|
||
|
* Between those common lines, the patience diff algorithm is applied
|
||
|
* recursively, until no unique line pairs can be found; these line ranges
|
||
|
* are handled by the well-known Myers algorithm.
|
||
|
*/
|
||
|
|
||
|
#define NON_UNIQUE ULONG_MAX
|
||
|
|
||
|
/*
|
||
|
* This is a hash mapping from line hash to line numbers in the first and
|
||
|
* second file.
|
||
|
*/
|
||
|
struct hashmap {
|
||
|
int nr, alloc;
|
||
|
struct entry {
|
||
|
unsigned long hash;
|
||
|
/*
|
||
|
* 0 = unused entry, 1 = first line, 2 = second, etc.
|
||
|
* line2 is NON_UNIQUE if the line is not unique
|
||
|
* in either the first or the second file.
|
||
|
*/
|
||
|
unsigned long line1, line2;
|
||
|
/*
|
||
|
* "next" & "previous" are used for the longest common
|
||
|
* sequence;
|
||
|
* initially, "next" reflects only the order in file1.
|
||
|
*/
|
||
|
struct entry *next, *previous;
|
||
|
} *entries, *first, *last;
|
||
|
/* were common records found? */
|
||
|
unsigned long has_matches;
|
||
|
mmfile_t *file1, *file2;
|
||
|
xdfenv_t *env;
|
||
|
xpparam_t const *xpp;
|
||
|
};
|
||
|
|
||
|
/* The argument "pass" is 1 for the first file, 2 for the second. */
|
||
|
static void insert_record(int line, struct hashmap *map, int pass)
|
||
|
{
|
||
|
xrecord_t **records = pass == 1 ?
|
||
|
map->env->xdf1.recs : map->env->xdf2.recs;
|
||
|
xrecord_t *record = records[line - 1], *other;
|
||
|
/*
|
||
|
* After xdl_prepare_env() (or more precisely, due to
|
||
|
* xdl_classify_record()), the "ha" member of the records (AKA lines)
|
||
|
* is _not_ the hash anymore, but a linearized version of it. In
|
||
|
* other words, the "ha" member is guaranteed to start with 0 and
|
||
|
* the second record's ha can only be 0 or 1, etc.
|
||
|
*
|
||
|
* So we multiply ha by 2 in the hope that the hashing was
|
||
|
* "unique enough".
|
||
|
*/
|
||
|
int index = (int)((record->ha << 1) % map->alloc);
|
||
|
|
||
|
while (map->entries[index].line1) {
|
||
|
other = map->env->xdf1.recs[map->entries[index].line1 - 1];
|
||
|
if (map->entries[index].hash != record->ha ||
|
||
|
!xdl_recmatch(record->ptr, record->size,
|
||
|
other->ptr, other->size,
|
||
|
map->xpp->flags)) {
|
||
|
if (++index >= map->alloc)
|
||
|
index = 0;
|
||
|
continue;
|
||
|
}
|
||
|
if (pass == 2)
|
||
|
map->has_matches = 1;
|
||
|
if (pass == 1 || map->entries[index].line2)
|
||
|
map->entries[index].line2 = NON_UNIQUE;
|
||
|
else
|
||
|
map->entries[index].line2 = line;
|
||
|
return;
|
||
|
}
|
||
|
if (pass == 2)
|
||
|
return;
|
||
|
map->entries[index].line1 = line;
|
||
|
map->entries[index].hash = record->ha;
|
||
|
if (!map->first)
|
||
|
map->first = map->entries + index;
|
||
|
if (map->last) {
|
||
|
map->last->next = map->entries + index;
|
||
|
map->entries[index].previous = map->last;
|
||
|
}
|
||
|
map->last = map->entries + index;
|
||
|
map->nr++;
|
||
|
}
|
||
|
|
||
|
/*
|
||
|
* This function has to be called for each recursion into the inter-hunk
|
||
|
* parts, as previously non-unique lines can become unique when being
|
||
|
* restricted to a smaller part of the files.
|
||
|
*
|
||
|
* It is assumed that env has been prepared using xdl_prepare().
|
||
|
*/
|
||
|
static int fill_hashmap(mmfile_t *file1, mmfile_t *file2,
|
||
|
xpparam_t const *xpp, xdfenv_t *env,
|
||
|
struct hashmap *result,
|
||
|
int line1, int count1, int line2, int count2)
|
||
|
{
|
||
|
result->file1 = file1;
|
||
|
result->file2 = file2;
|
||
|
result->xpp = xpp;
|
||
|
result->env = env;
|
||
|
|
||
|
/* We know exactly how large we want the hash map */
|
||
|
result->alloc = count1 * 2;
|
||
|
result->entries = (struct entry *)
|
||
|
xdl_malloc(result->alloc * sizeof(struct entry));
|
||
|
if (!result->entries)
|
||
|
return -1;
|
||
|
memset(result->entries, 0, result->alloc * sizeof(struct entry));
|
||
|
|
||
|
/* First, fill with entries from the first file */
|
||
|
while (count1--)
|
||
|
insert_record(line1++, result, 1);
|
||
|
|
||
|
/* Then search for matches in the second file */
|
||
|
while (count2--)
|
||
|
insert_record(line2++, result, 2);
|
||
|
|
||
|
return 0;
|
||
|
}
|
||
|
|
||
|
/*
|
||
|
* Find the longest sequence with a smaller last element (meaning a smaller
|
||
|
* line2, as we construct the sequence with entries ordered by line1).
|
||
|
*/
|
||
|
static int binary_search(struct entry **sequence, int longest,
|
||
|
struct entry *entry)
|
||
|
{
|
||
|
int left = -1, right = longest;
|
||
|
|
||
|
while (left + 1 < right) {
|
||
|
int middle = (left + right) / 2;
|
||
|
/* by construction, no two entries can be equal */
|
||
|
if (sequence[middle]->line2 > entry->line2)
|
||
|
right = middle;
|
||
|
else
|
||
|
left = middle;
|
||
|
}
|
||
|
/* return the index in "sequence", _not_ the sequence length */
|
||
|
return left;
|
||
|
}
|
||
|
|
||
|
/*
|
||
|
* The idea is to start with the list of common unique lines sorted by
|
||
|
* the order in file1. For each of these pairs, the longest (partial)
|
||
|
* sequence whose last element's line2 is smaller is determined.
|
||
|
*
|
||
|
* For efficiency, the sequences are kept in a list containing exactly one
|
||
|
* item per sequence length: the sequence with the smallest last
|
||
|
* element (in terms of line2).
|
||
|
*/
|
||
|
static struct entry *find_longest_common_sequence(struct hashmap *map)
|
||
|
{
|
||
|
struct entry **sequence = xdl_malloc(map->nr * sizeof(struct entry *));
|
||
|
int longest = 0, i;
|
||
|
struct entry *entry;
|
||
|
|
||
|
for (entry = map->first; entry; entry = entry->next) {
|
||
|
if (!entry->line2 || entry->line2 == NON_UNIQUE)
|
||
|
continue;
|
||
|
i = binary_search(sequence, longest, entry);
|
||
|
entry->previous = i < 0 ? NULL : sequence[i];
|
||
|
sequence[++i] = entry;
|
||
|
if (i == longest)
|
||
|
longest++;
|
||
|
}
|
||
|
|
||
|
/* No common unique lines were found */
|
||
|
if (!longest) {
|
||
|
xdl_free(sequence);
|
||
|
return NULL;
|
||
|
}
|
||
|
|
||
|
/* Iterate starting at the last element, adjusting the "next" members */
|
||
|
entry = sequence[longest - 1];
|
||
|
entry->next = NULL;
|
||
|
while (entry->previous) {
|
||
|
entry->previous->next = entry;
|
||
|
entry = entry->previous;
|
||
|
}
|
||
|
xdl_free(sequence);
|
||
|
return entry;
|
||
|
}
|
||
|
|
||
|
static int match(struct hashmap *map, int line1, int line2)
|
||
|
{
|
||
|
xrecord_t *record1 = map->env->xdf1.recs[line1 - 1];
|
||
|
xrecord_t *record2 = map->env->xdf2.recs[line2 - 1];
|
||
|
return xdl_recmatch(record1->ptr, record1->size,
|
||
|
record2->ptr, record2->size, map->xpp->flags);
|
||
|
}
|
||
|
|
||
|
static int patience_diff(mmfile_t *file1, mmfile_t *file2,
|
||
|
xpparam_t const *xpp, xdfenv_t *env,
|
||
|
int line1, int count1, int line2, int count2);
|
||
|
|
||
|
static int walk_common_sequence(struct hashmap *map, struct entry *first,
|
||
|
int line1, int count1, int line2, int count2)
|
||
|
{
|
||
|
int end1 = line1 + count1, end2 = line2 + count2;
|
||
|
int next1, next2;
|
||
|
|
||
|
for (;;) {
|
||
|
/* Try to grow the line ranges of common lines */
|
||
|
if (first) {
|
||
|
next1 = first->line1;
|
||
|
next2 = first->line2;
|
||
|
while (next1 > line1 && next2 > line2 &&
|
||
|
match(map, next1 - 1, next2 - 1)) {
|
||
|
next1--;
|
||
|
next2--;
|
||
|
}
|
||
|
} else {
|
||
|
next1 = end1;
|
||
|
next2 = end2;
|
||
|
}
|
||
|
while (line1 < next1 && line2 < next2 &&
|
||
|
match(map, line1, line2)) {
|
||
|
line1++;
|
||
|
line2++;
|
||
|
}
|
||
|
|
||
|
/* Recurse */
|
||
|
if (next1 > line1 || next2 > line2) {
|
||
|
struct hashmap submap;
|
||
|
|
||
|
memset(&submap, 0, sizeof(submap));
|
||
|
if (patience_diff(map->file1, map->file2,
|
||
|
map->xpp, map->env,
|
||
|
line1, next1 - line1,
|
||
|
line2, next2 - line2))
|
||
|
return -1;
|
||
|
}
|
||
|
|
||
|
if (!first)
|
||
|
return 0;
|
||
|
|
||
|
while (first->next &&
|
||
|
first->next->line1 == first->line1 + 1 &&
|
||
|
first->next->line2 == first->line2 + 1)
|
||
|
first = first->next;
|
||
|
|
||
|
line1 = first->line1 + 1;
|
||
|
line2 = first->line2 + 1;
|
||
|
|
||
|
first = first->next;
|
||
|
}
|
||
|
}
|
||
|
|
||
|
static int fall_back_to_classic_diff(struct hashmap *map,
|
||
|
int line1, int count1, int line2, int count2)
|
||
|
{
|
||
|
/*
|
||
|
* This probably does not work outside Git, since
|
||
|
* we have a very simple mmfile structure.
|
||
|
*
|
||
|
* Note: ideally, we would reuse the prepared environment, but
|
||
|
* the libxdiff interface does not (yet) allow for diffing only
|
||
|
* ranges of lines instead of the whole files.
|
||
|
*/
|
||
|
mmfile_t subfile1, subfile2;
|
||
|
xpparam_t xpp;
|
||
|
xdfenv_t env;
|
||
|
|
||
|
subfile1.ptr = (char *)map->env->xdf1.recs[line1 - 1]->ptr;
|
||
|
subfile1.size = map->env->xdf1.recs[line1 + count1 - 2]->ptr +
|
||
|
map->env->xdf1.recs[line1 + count1 - 2]->size - subfile1.ptr;
|
||
|
subfile2.ptr = (char *)map->env->xdf2.recs[line2 - 1]->ptr;
|
||
|
subfile2.size = map->env->xdf2.recs[line2 + count2 - 2]->ptr +
|
||
|
map->env->xdf2.recs[line2 + count2 - 2]->size - subfile2.ptr;
|
||
|
xpp.flags = map->xpp->flags & ~XDF_PATIENCE_DIFF;
|
||
|
if (xdl_do_diff(&subfile1, &subfile2, &xpp, &env) < 0)
|
||
|
return -1;
|
||
|
|
||
|
memcpy(map->env->xdf1.rchg + line1 - 1, env.xdf1.rchg, count1);
|
||
|
memcpy(map->env->xdf2.rchg + line2 - 1, env.xdf2.rchg, count2);
|
||
|
|
||
|
xdl_free_env(&env);
|
||
|
|
||
|
return 0;
|
||
|
}
|
||
|
|
||
|
/*
|
||
|
* Recursively find the longest common sequence of unique lines,
|
||
|
* and if none was found, ask xdl_do_diff() to do the job.
|
||
|
*
|
||
|
* This function assumes that env was prepared with xdl_prepare_env().
|
||
|
*/
|
||
|
static int patience_diff(mmfile_t *file1, mmfile_t *file2,
|
||
|
xpparam_t const *xpp, xdfenv_t *env,
|
||
|
int line1, int count1, int line2, int count2)
|
||
|
{
|
||
|
struct hashmap map;
|
||
|
struct entry *first;
|
||
|
int result = 0;
|
||
|
|
||
|
/* trivial case: one side is empty */
|
||
|
if (!count1) {
|
||
|
while(count2--)
|
||
|
env->xdf2.rchg[line2++ - 1] = 1;
|
||
|
return 0;
|
||
|
} else if (!count2) {
|
||
|
while(count1--)
|
||
|
env->xdf1.rchg[line1++ - 1] = 1;
|
||
|
return 0;
|
||
|
}
|
||
|
|
||
|
memset(&map, 0, sizeof(map));
|
||
|
if (fill_hashmap(file1, file2, xpp, env, &map,
|
||
|
line1, count1, line2, count2))
|
||
|
return -1;
|
||
|
|
||
|
/* are there any matching lines at all? */
|
||
|
if (!map.has_matches) {
|
||
|
while(count1--)
|
||
|
env->xdf1.rchg[line1++ - 1] = 1;
|
||
|
while(count2--)
|
||
|
env->xdf2.rchg[line2++ - 1] = 1;
|
||
|
xdl_free(map.entries);
|
||
|
return 0;
|
||
|
}
|
||
|
|
||
|
first = find_longest_common_sequence(&map);
|
||
|
if (first)
|
||
|
result = walk_common_sequence(&map, first,
|
||
|
line1, count1, line2, count2);
|
||
|
else
|
||
|
result = fall_back_to_classic_diff(&map,
|
||
|
line1, count1, line2, count2);
|
||
|
|
||
|
xdl_free(map.entries);
|
||
|
return result;
|
||
|
}
|
||
|
|
||
|
int xdl_do_patience_diff(mmfile_t *file1, mmfile_t *file2,
|
||
|
xpparam_t const *xpp, xdfenv_t *env)
|
||
|
{
|
||
|
if (xdl_prepare_env(file1, file2, xpp, env) < 0)
|
||
|
return -1;
|
||
|
|
||
|
/* environment is cleaned up in xdl_diff() */
|
||
|
return patience_diff(file1, file2, xpp, env,
|
||
|
1, env->xdf1.nrec, 1, env->xdf2.nrec);
|
||
|
}
|