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With -u flag, git-checkout-cache picks up the stat information from newly created file and updates the cache. This removes the need to run git-update-cache --refresh immediately after running git-checkout-cache. Signed-off-by: Junio C Hamano <junkio@cox.net> Signed-off-by: Linus Torvalds <torvalds@osdl.org>
106 lines
2.9 KiB
Text
106 lines
2.9 KiB
Text
git-checkout-cache(1)
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=====================
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v0.1, May 2005
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NAME
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----
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git-checkout-cache - Copy files from the cache to the working directory
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SYNOPSIS
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--------
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'git-checkout-cache' [-u] [-q] [-a] [-f] [-n] [--prefix=<string>]
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[--] <file>...
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DESCRIPTION
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-----------
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Will copy all files listed from the cache to the working directory
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(not overwriting existing files).
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OPTIONS
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-------
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-u::
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update stat information for the checked out entries in
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the cache file.
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-q::
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be quiet if files exist or are not in the cache
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-f::
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forces overwrite of existing files
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-a::
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checks out all files in the cache (will then continue to
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process listed files).
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-n::
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Don't checkout new files, only refresh files already checked
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out.
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--prefix=<string>::
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When creating files, prepend <string> (usually a directory
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including a trailing /)
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--::
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Do not interpret any more arguments as options.
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Note that the order of the flags matters:
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git-checkout-cache -a -f file.c
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will first check out all files listed in the cache (but not overwrite
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any old ones), and then force-checkout `file.c` a second time (ie that
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one *will* overwrite any old contents with the same filename).
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Also, just doing "git-checkout-cache" does nothing. You probably meant
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"git-checkout-cache -a". And if you want to force it, you want
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"git-checkout-cache -f -a".
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Intuitiveness is not the goal here. Repeatability is. The reason for
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the "no arguments means no work" thing is that from scripts you are
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supposed to be able to do things like:
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find . -name '*.h' -print0 | xargs -0 git-checkout-cache -f --
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which will force all existing `*.h` files to be replaced with their
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cached copies. If an empty command line implied "all", then this would
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force-refresh everything in the cache, which was not the point.
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To update and refresh only the files already checked out:
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git-checkout-cache -n -f -a && git-update-cache --ignore-missing --refresh
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Oh, and the "--" is just a good idea when you know the rest will be
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filenames. Just so that you wouldn't have a filename of "-a" causing
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problems (not possible in the above example, but get used to it in
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scripting!).
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The prefix ability basically makes it trivial to use
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git-checkout-cache as an "export as tree" function. Just read the
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desired tree into the index, and do a
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git-checkout-cache --prefix=git-export-dir/ -a
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and git-checkout-cache will "export" the cache into the specified
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directory.
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NOTE The final "/" is important. The exported name is literally just
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prefixed with the specified string, so you can also do something like
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git-checkout-cache --prefix=.merged- Makefile
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to check out the currently cached copy of `Makefile` into the file
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`.merged-Makefile`
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Author
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------
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Written by Linus Torvalds <torvalds@osdl.org>
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Documentation
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--------------
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Documentation by David Greaves, Junio C Hamano and the git-list <git@vger.kernel.org>.
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GIT
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---
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Part of the link:git.html[git] suite
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